いろいろ (a+b+c)3 ka formula 163009-(a+b+c)2 ka formula
Using determinants, we can write the result as a × b = a 2 a 3 b 2 b 3 i − a 1 a 3 b 1 b 3 j a 1 a 2 b 1 b 2 k Looking at the formula for the 3 × 3 determinant, we see that the formula for a cross product looks a lot like the formula for the 3 × 3 determinantExample 3 A = {a, b, c, d, e}, B = {x, y, z} and C = {a, e, x} find the value of n(AUBUC) Solution n(AUBUC)=n(A)n(B) n(C)n(AnB)n(BnC)n(CnA)n(AnBnC) n (A) = 5 n (B) = 3 n (C) = 3 A n B = {a, b, c, d, e} n {x, y, z} = { } n (A n B) = 0 B n C = {x, y, z} n {a, e, x} = {x} n (B n C) = 1The Triangle Formula are given below as, Perimeter of a triangle = a b c \Area\; Ncert Class 9 Maths Lab Manual Verify The Algebraic Identity A B C A B C 2ab 2bc 2ca Cbse Tuts (a+b+c)2 ka formula